A 6 m simply supported beam carries an ultimate live load of 50kN at midspan. Determine the plastic moment of the beam.
External deformation = Internal deformation.
EWD= IWD
EWD= Ultimate load ×\times× δ\deltaδ
while δ=l2θ\delta = \frac{l}{2} \thetaδ=2lθ
EWD = wu×l2θw_u \times \frac{l}{2} \thetawu×2lθ
from the diagram
IWD = MPθ+MP2θ+MP0=4MPθM_P\theta + M_P2\theta + M_P0 = 4M_P\thetaMPθ+MP2θ+MP0=4MPθ
IF IWD = EWD
then 4MPθ=wu×l2θ4M_P\theta= w_u \times \frac{l}{2} \theta4MPθ=wu×2lθ
MP=wuL8=50×68=37.5KNmM_P= \frac{wuL}{8} = \frac{50 \times 6}{8} = 37.5 KNmMP=8wuL=850×6=37.5KNm
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