The average accident on a certain road section is at 2.4 per day. What is tge probability that there will be 12 accidents in a week?
P(X=x)=e−λλxx!λ=2.4×7=16.8P(X=12)=e−16.816.81212!=0.0533P(X=x) = \frac{e^{-λ}λ^x}{x!} \\ λ=2.4 \times 7 = 16.8 \\ P(X=12) = \frac{e^{-16.8}16.8^12}{12!} = 0.0533P(X=x)=x!e−λλxλ=2.4×7=16.8P(X=12)=12!e−16.816.812=0.0533
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