Answer to Question #191103 in Civil and Environmental Engineering for Joshua

Question #191103

A binomial distribution consists of 120 trials, with a success probability of 43% . determine the mean and standard deviation


1
Expert's answer
2021-05-21T12:07:01-0400

mean μ=np\mu = np


μ=120×0.43=51.6\mu = 120 \times 0.43 = 51.6


standard deviation= σ\sigma


σ2=np(1p)=120×0.43(10.43)\sigma^2= np(1-p)= 120\times 0.43(1-0.43)


σ2=29.412\sigma^2= 29.412


σ\sigma = 29.412=5.423\sqrt{29.412}= 5.423


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