Determine the force between a point charge of -100 μc and +50 μc when they are 200 cm apart in a vacuum.
According to coulomb's law ,
F= "k\\times \\frac{q_1q_2}{d^2}"
F= "9\\times 10^9 \\times \\frac{100\\times 10^{-6} \\times 50 \\times 10^{-6}}{2}" = 22.5 N
F= 22.5 N
Comments
Leave a comment