Question

Determine the force between a point charge of -100 μc and +50 μc when they are 200 cm apart in a vacuum.

Answer 1

According to coulomb's law ,

F= $k\times \frac{q_1q_2}{d^2}$

F= $9\times 10^9 \times \frac{100\times 10^{-6} \times 50 \times 10^{-6}}{2}$ = 22.5 N

F= 22.5 N