Question

A horizontal arm, capable of rotation about a vertical shaft, carries a mass of 2.5 kg, bolted to it by a 1 cm bolt at a distance of 50 cm from the axis of the shaft. The axis of the bolt is vertical. if the ultimate shearing strength of the bolt is 50 MN/ m ², at what speed will the bolt snap?

Answer 1

From the formula of circular vertical motion

where T= 50 MN/ m ²

^{and m = 2.5 Kg , g= 10 m/s}$^2$ r = 50cm

$T= mg + \frac{mv^2}{r}$

$50= 2.5 \times 10 + \frac{m2.5v^2}{0.5}$

50= $5v^2 + 25$

5$v^2$ =25

v= 2.236 m/s