Determine the volume of the solid formed when the region enclosed by the curve y=√x, the x-axis and the linex= 4, is revolved about the line x= 4.
Using shell method, the volume of the solid of the revolution is:
"V = \\int_0^4 2 \\pi \\cdot (4-x) \\sqrt{x} dx = 2 \\pi (\\frac{8}{3}x^{3\/2} - \\frac{2}{5}x^{5\/2})|_0^4 = \\frac{256}{15}\\pi".
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