Determine the volume of the solid formed when the region enclosed by the curve y=√x, the x-axis and the linex= 4, is revolved about the line x= 4.
Using shell method, the volume of the solid of the revolution is:
V=∫042π⋅(4−x)xdx=2π(83x3/2−25x5/2)∣04=25615πV = \int_0^4 2 \pi \cdot (4-x) \sqrt{x} dx = 2 \pi (\frac{8}{3}x^{3/2} - \frac{2}{5}x^{5/2})|_0^4 = \frac{256}{15}\piV=∫042π⋅(4−x)xdx=2π(38x3/2−52x5/2)∣04=15256π.
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