Find the area bounded by the curve x²=y+2 and the line x+y=0.
Let us find the x points of intersection of two graphs y1(x)=x2−2y_1(x) = x^2 - 2y1(x)=x2−2 and y2(x)=−xy_2(x) = - xy2(x)=−x by solving corresponding quadratic equation x2−2=−xx^2 - 2 = -xx2−2=−x. It has roots x=−2,x=1x = -2 , x = 1x=−2,x=1.
Hence, the area between two curves is:
S=∫−21(−x−(x2−2))dx=(−x22−x33+2x)∣−21=92S = \int_{-2}^1 (-x - (x^2 - 2 )) d x = (-\frac{x^2}{2} - \frac{x^3}{3} + 2 x)|_{-2}^1 = \frac{9}{2}S=∫−21(−x−(x2−2))dx=(−2x2−3x3+2x)∣−21=29.
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