Answer to Question #177610 in Civil and Environmental Engineering for Mae

Question

Calculate the area bounded by y=x3

, x=0 and y=3.

Answer 1

 y=x3

, x=0 and y=3.

f(x)= x³ and g(x) = 3

given that,

x=0

in order to find second interval, we have to find the point of intersection of y=x³ and y=3

Hence, 3=x³ therefore x=1.442

hence the interval is, [0, 1.442]

A = $\intop$^1.442[3-X³]dx

⁰

A= [ 3X- X^2.08/2.08]^1.442

⁰

A= [4.326- 1.029]-[0-0]

A= 5.586 sq. units