A rectangular lot was measured using a 50 m metallic tape which was 1.02 cm too short. The recorded distances were 170.55 m long by 137.05 m wide. What is the error in area introduced due to the erroneous length of tape?
Length of tape = 50m
Convert to Centimetres where 1m = 100cm
50m = 50 x 100 = 5000cm
Measured Length = 170.55m
Measured Length in cm = 170.55 x 100 = 17055cm
Measured Width = 137.05m
Measured Length in cm = 137.05 x 100 = 13705cm
Area is given by Length x Width.
Measured area = 17055 x 13705 = 233,738,775 cm2
Actual length.
If 5000cm generate an error of 1.02cm, what about 17055 cm
(17055 x 1.02)/5000 = 3.47 cm
Actual length = 17055 + 3.47 = 17058.47cm
Actual Width.
If 5000cm generate an error of 1.02cm, what about 13705 cm
(13705 x 1.02)/5000 = 2.79 cm
Actual length = 13705 + 2.79 = 13707.79 cm
Actual area = 17058.47 x 13707.79 = 233,833,924.48 cm2
Error in Area = 233,833,924.48 - 233,738,775 = 95,149.48 cm2
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