Answer to Question #147865 in Civil and Environmental Engineering for Raihan

Question #147865
Consider a mercury manometer connected to a tank of water, as shown in the diagram below. Please calculate the ratio of hm to hw. (The specific gravity of mercury=13.56)
1
Expert's answer
2020-12-22T05:03:17-0500



Solution

The pressure at point A is PA= yw (hw + hm)

The pressure at point B is PB= 2ywhm

PA=PB; yw(hw + hm) = 2ywhm

ywhm = (2ym - yw)hm

hw/hm = (2ym - yw)/yw = (2SG -1)/1 = 2 x 13.6 - 1

= 26.2

Therefore, the ratio hw/hm = 26.2


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