Answer to Question #147865 in Civil and Environmental Engineering for Raihan

Question

Consider a mercury manometer connected to a tank of water, as shown in the diagram below. Please calculate the ratio of hm to hw. (The specific gravity of mercury=13.56)

Answer 1

Solution

The pressure at point A is P_A= y_w (h_w + h_m)

The pressure at point B is P_B= 2y_wh_m

P_A=P_B; y_w(h_w + h_m) = 2y_wh_m

y_wh_m = (2y_m - y_w)h_m

h_w/h_m = (2y_m - y_w)/y_w = (2SG -1)/1 = 2 x 13.6 - 1

= 26.2

Therefore, the ratio h_w/h_m = 26.2