Answer to Question #119034 in Civil and Environmental Engineering for Eddyq
Question #119034
A straight bar of uniform cross section is subject to an axial tension, the cross sectional area of the bar is 50mm^2 and it's length is 2mm under a load of 40kN. Find the modulus of elasticity
Expert's answer
"\\sigma=E\\cdot\\epsilon=E\\cdot\\frac{\\Delta l}{l}=\\frac{F}{A}\\to E=\\frac{F}{A}\\cdot\\frac{l}{\\Delta l}"
Assume that "\\Delta l=1 mm"
So, we have
"E=\\frac{F}{A}\\cdot\\frac{l}{\\Delta l}=\\frac{40000}{50\\cdot10^{-6}}\\cdot\\frac{0.002}{0.001}=1600 MPa"
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