Question

The value of the second ionisation energy of calcium is 1150KJ.mol-1
Which equation correctly represent this statement?
A. Ca^+(g) = Ca^2+(g) + e^-
Delta = +1150KJ.mol-1
B. Ca(g) = Ca^2+(g) + 2^e^-
Delta = +1150KJ.mol-1
C. Ca^+(g) = Ca^2+(g) + e^-
Delta = -1150KJ.mol-1
D. Ca(g) = Ca^2+(g) + 2e^-
Delta = -1150KJ.mol-1

Answer 1

(A) Ca⁺_(g)=Ca²⁺(g) + e^-

Delta= +1150 kJ/mole