Question

b) Nitrous oxide decomposes according to the second order rate equation 2N₂0→2N₂ +0₂ The rate constant is 977 cm

Answer 1

for a second order reaction;

$\dfrac{1}{[A]}= \dfrac{1}{[A_0]}+kt$

Assuming that the rate constant is $977\ cMs^{-1} = 9.77\ Ms^{-1}$

The equation becomes;

$\dfrac{1}{[A]}= \dfrac{1}{[A_0]}+9.77t$