Question #235098

12)Use Cauchy integral formula for derivatives evaluate ∮c z²-2z/(z+1)^2 (z²+4)dz, where C is |z + 2) <2.


1
Expert's answer
2021-09-12T00:32:28-0400

cz22z/(z+1)2(z2+4)dz∮c z²-2z/(z+1)^2 (z²+4)dz

=𝐵(𝑖/2)1𝑧2+1𝑑𝑧==∮𝐵(𝑖/2)1𝑧2+1𝑑𝑧=∮

=B2i/2(1/2i)/(z+1)2dzB2=∮_{B2}{i/2} (1/2i)/(z+1)^2 dz-\oint_{B2}

=12i12i=\frac{1}{2i}-\frac{1}{2i}

=0=0


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