Answer to Question #234132 in Chemical Engineering for Thando

Question

The indicating liquid in the manometer shown in the figure below is water and benzene with a density of 880 kg/m³. These two liquids are essentially insoluble in each other. If the two liquids are essentially insoluble in each other. If the manometer reading is ΔZ = 37.19 cm of water, what is the pressure difference P₁ - P₂ in kN/m². Show detailed calculations.

Answer 1

guage pressure = $\rho × g × h$ =$37.19/100 × 9.8 × 880$ = 3207.27 Pa

$\therefore$ P₂ - P₁ = 3207.3 Pa