Answer to Question #231351 in Chemical Engineering for pavani

Question

11)Solve the PDE (x+y²)p+yq=z+x².

Answer 1

this is hyperbolic paraboloid $(x+y²)p+yq=z+x²$

$x^2-(x+y²)p+yq=z$

real solution is;

$0=x^2-px+py^2+yq$