11)Solve the PDE (x+y²)p+yq=z+x².
this is hyperbolic paraboloid (x+y2)p+yq=z+x2(x+y²)p+yq=z+x²(x+y2)p+yq=z+x2
x2−(x+y2)p+yq=zx^2-(x+y²)p+yq=zx2−(x+y2)p+yq=z
real solution is;
0=x2−px+py2+yq0=x^2-px+py^2+yq0=x2−px+py2+yq
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