Answer to Question #231329 in Chemical Engineering for pavani

Question

Find the Laplace transform of the periodic function f(t)=t ,0≤t<1 ; 2-t,1≤t≤2 and f(t+2)=f(t)?

Answer 1

Here f(t)=t, your limits will not varay from +inf to -inf but from 0 to 2.

For periodic function however it takes a different form which nothing but a highly specialized one by using certain constraints.

The answer will be like :

1/(1-e^-2s)*[-((2*e^-2s)/s)-((e^-2s)/(s^2))+1/s^2]