Answer to Question #229236 in Chemical Engineering for Lokika

Question

Solution of (D³ - 2D² - 3D)y = 0,, choose the correct answer

A) y = C1.₁e^{x} + C₂е^{-x }+ С3.e^{3x} B) y = C1e^x + C₂е^{-x} + С3.e^{-3x}

C) y = C1+C₂е^{-x} + С3.e^{3x}

D) y = C₁+C₂е^{-x} + С3e^{-3x}

Answer 1

(C) y=C₁+C₂e^{-X} + C₃e^{3X}