Answer to Question #227669 in Chemical Engineering for Lokika

Question

What is the thermal diffusivity (in m³/s) of the material having properties, p-7500 kg/m³, Cp 400 J/(kg-K), k-15 W/(m-K).?

Answer 1

Thermal diffusivity=(Thermal Conductivity)/(density)(spe cific heat at constant pressures).

Thermal diffusivity = 15/7500*400

=0.5×10^-5W.m²/J

Watt is J/s

Thermal diffusivity=0.5×10^-5m²/s