Question #223864

Evaluate ∫0^{π/2a}asinαxdx,α>0 by using Leibniz formula.`


Expert's answer

0π/2aasinaxdx=cosax0π/2a=cosπ/2cos0=01=1\int_0^{π/2a}a\sin axdx=\cos ax|_0^{\pi/2a}\\=\cos \pi/2-\cos 0=0-1=-1


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