Answer to Question #223819 in Chemical Engineering for Lokika

Question #223819

limz→0 z^{2}-sinz/z


1
Expert's answer
2021-08-11T07:28:40-0400

"\\lim _{z\\to \\:0}\\left(z^2-\\frac{\\sin \\left(z\\right)}{z}\\right)\\\\\n\\lim _{x\\to a}\\left[f\\left(x\\right)\\pm g\\left(x\\right)\\right]=\\lim _{x\\to a}f\\left(x\\right)\\pm \\lim _{x\\to a}g\\left(x\\right)\\\\\nWith\\:the\\:exception\\:of\\:indeterminate\\:form\\\\\n=\\lim _{z\\to \\:0}\\left(z^2\\right)-\\lim _{z\\to \\:0}\\left(\\frac{\\sin \\left(z\\right)}{z}\\right)\\\\\n=0-1\\\\\n=-1"


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