Part a
Tr=TcT=282.3328.15=1.162;Pr=PcP=50.435=0.694
From the table , Zo=0.838,Z1=0.033
The correlation of the comprehensibility factor is Z=Z0+ωZ1=0.838+0.087∗0.033=0.841
Hence, PV=ZnRT⟹n=Mm=2818=0.6428Kmol
V=PZnRT=35∗1050.841∗0.6428∗103∗8.314∗32815=0.421m3
Part b
Tr=TcT=282.3323.15=1.145;Pr=PcP=50.4115=2.282
From the table , Zo=0.482,Z1=0.126
The correlation of the comprehensibility factor is Z=Z0+ωZ1=0.482+0.087∗0.126=0.493
Hence, PV=ZnRT⟹n=ZRTPV=0.493∗8.314∗323.15115∗105∗0.25=2.171Kmol
Comments