A 10.00-cm shaft rides in a 10.03-cm sleeve 12 cm long, the clearance space being filled with lubricating oil at 40oC (μ=0.11 Pa-s). Calculate the energy, in W, generated when the shaft turns at 100 rpm
Solution.
dv = =100/60[π(0.10)]= 0.5236m/s
dx = (0.1003 - 0.1000)/2= 0.00015m
= (d/dx) = (0.11)(0.5236)/0.00015 = 384.0N/m2
Ff = A = 384.0 [ π(0.12)(0.10)] = 14.48N
Rate of energy loss = Ff= (14.48)(0.5236) = 7.582N . m/s = 7.582W.
Answer.
7.582W
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