Basis : 1 mol of gaseous propane.
C3H8+5O2→3CO2+4H2O
1mol C3H8=4 moleH2O
i.e when 1mol of C3H8 burnt,4 moles of H2O are produced.
Water produced = 4*18 = 72 g = 72∗10−3g
NHV=Net heating value=GHV−Latent heat ofwater vapor
=2219.71−72∗10−3∗2442.5
=2043.85 kJ/mol
Comments
Thank you so much