the number of train commuters who fail to pay for their tickets in a certain region has a Poisson distribution with a mean of 3 per train. if there are 5000 trains per month in a region, find:
a) the expected number of trains with more than 2 non fare-paying commuters
b) the loss to the train company given that the average cost of a train is $10.00
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Expert's answer
2012-02-16T09:29:55-0500
a) P = a^m/m!*e^(-a) = 2^3/3!*e^(-2) = 0.18 N = 0.18*5000 = 900 b) 900*$10 = $9000
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