Subtracting the sum of 4π₯ β π₯ 3 and βπ₯ + 5 from β6 β 4π₯ 3 + 3π₯
[1] 6π₯ 3 β 11
[2] β3π₯ 3 β 11
[3] β3π₯ 3 + 7π₯ β 1
[4] 6π₯ 3 + 7π₯ β 11
β6β4π₯3+3π₯β(4π₯βπ₯3βπ₯+5)=β6β4π₯3+3π₯β4π₯+π₯3+π₯β5=β3x3β11.β6 β 4π₯^3 + 3π₯ - (4π₯ β π₯^3 β π₯ + 5) = β6 β 4π₯^3 + 3π₯ - 4π₯ + π₯^3 + π₯ - 5 = -3x^3 - 11.β6β4x3+3xβ(4xβx3βx+5)=β6β4x3+3xβ4x+x3+xβ5=β3x3β11.
So, the correct answer is [2].
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