Answer to Question #319648 in Economics for Bea

Question #319648

Subtracting the sum of 4π‘₯ βˆ’ π‘₯ 3 and βˆ’π‘₯ + 5 from βˆ’6 βˆ’ 4π‘₯ 3 + 3π‘₯

[1] 6π‘₯ 3 βˆ’ 11

[2] βˆ’3π‘₯ 3 βˆ’ 11

[3] βˆ’3π‘₯ 3 + 7π‘₯ βˆ’ 1

[4] 6π‘₯ 3 + 7π‘₯ βˆ’ 11


1
Expert's answer
2022-03-29T16:47:41-0400

βˆ’6βˆ’4π‘₯3+3π‘₯βˆ’(4π‘₯βˆ’π‘₯3βˆ’π‘₯+5)=βˆ’6βˆ’4π‘₯3+3π‘₯βˆ’4π‘₯+π‘₯3+π‘₯βˆ’5=βˆ’3x3βˆ’11.βˆ’6 βˆ’ 4π‘₯^3 + 3π‘₯ - (4π‘₯ βˆ’ π‘₯^3 βˆ’ π‘₯ + 5) = βˆ’6 βˆ’ 4π‘₯^3 + 3π‘₯ - 4π‘₯ + π‘₯^3 + π‘₯ - 5 = -3x^3 - 11.

So, the correct answer is [2].


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