Question #255351
Statistics Q. The number of calls received per hour at a call centre by a sample of different operators are given below: 5,4,7,6,8,10,11,0,7,18 1. Find the arithmetic mean and median and standard deviation. 2. If the last observation is 28 instead of 18, how will the mean and median change? 3. Calculate a 15% trimmed mean
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Expert's answer
2021-10-24T18:13:18-0400

1 arithmetic mean: (5+4+7+6+8+10+11+0+7+18+1)/11=7(5+4+7+6+8+10+11+0+7+18+1)/11=7

median: 7; standard deviation:  (011)2+(111)2+(411)2+(511)2+(611)2+(711)2+(711)2+(811)2+(1011)2+(1111)2+(1811)2111=9\sqrt{\frac{(0-11)^2+(1-11)^2+(4-11)^2+(5-11)^2+(6-11)^2+(7-11)^2+(7-11)^2+(8-11)^2+(10-11)^2+(11-11)^2+(18-11)^2}{11-1}}=9

2 arithmetic mean: (5+4+7+6+8+10+11+0+7+28+1)/11=7.9(5+4+7+6+8+10+11+0+7+28+1)/11=7.9

median: 7

3 k=110.15=1.65k=11*0.15=1.65 ; R=1121.65=7.7R=11-2*1.65=7.7

trimmed mean: 17.7(10.65+4+5+6+7+7+8+10+110.65)=7.12\frac{1}{7.7}*(1*0.65+4+5+6+7+7+8+10+11*0.65)=7.12


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