If a car rented by the firm has bad tires, then the probability that it came from: a) agency C is:
P(A∣B)=0.5×0.060.3×0.15+0.2×0.1+0.5×0.06=0.030.095=0.32.P(A|B) = \frac{0.5×0.06}{0.3×0.15 + 0.2×0.1 + 0.5×0.06} = \frac{0.03} {0.095} = 0.32.P(A∣B)=0.3×0.15+0.2×0.1+0.5×0.060.5×0.06=0.0950.03=0.32.
b) agency A is:
P(A∣B)==0.3×0.150.095=0.47.P(A|B) = = \frac{0.3×0.15} {0.095} = 0.47.P(A∣B)==0.0950.3×0.15=0.47.
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