The maximum net revenue is obtained when MR = MC, so:
x = 75 - 3p, p = 25 - x/3,
MR=TR′(x)=25−2/3x,MR = TR'(x) = 25 - 2/3x,MR=TR′(x)=25−2/3x,
MC=TC′(x)=0.08x+3,MC = TC'(x) = 0.08x + 3,MC=TC′(x)=0.08x+3,
25−2/3x=0.08x+3,25 - 2/3x = 0.08x + 3,25−2/3x=0.08x+3,
0.41x = 22,
x = 53.7.
p = 25 - 53.7/3 = 7.11.
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