The surplus is an area below demand function and above the line p=64. So we need to calculate the integral on [0; 5]:
∫85−4x−x2−64=21x−2x2−x33=21∗5−2∗52−533=13.33(33)\int85-4x-x^2-64 = 21x - 2x^2 - \frac{x^3}{3} = 21*5-2*5^2 - \frac{5^3}{3} = 13.33(33)∫85−4x−x2−64=21x−2x2−3x3=21∗5−2∗52−353=13.33(33)
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