Question #57110

Tippalee Ventures Inc. provides helicopter tours of the wilderness. The fixed monthly cost for the helicopter, gear, and airport space is $42,500. The variable cost per tour is $6,500. The helicopter tours sell for $3,500 per person, and the helicopter seats three customers. Assuming every helicopter is filled to capacity, what is the break-even volume for the company? What is the break-even volume if each helicopter only carries two customers?
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2016-01-19T08:28:41-0500

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Question #57110, Economics / Microeconomics

Tippalee Ventures Inc. provides helicopter tours of the wilderness. The fixed monthly cost for the helicopter, gear, and airport space is $42,500. The variable cost per tour is $6,500. The helicopter tours sell for $3,500 per person, and the helicopter seats three customers.

a) Assuming every helicopter is filled to capacity, what is the break-even volume for the company?

b) What is the break-even volume if each helicopter only carries two customers?

Solution:

Costs function:


C(x)=$42,500+$6,500×xC(x) = \$42,500 + \$6,500 \times x


Revenue function:

a) Three customers per tour: R1(x)=$3,500×3xR_{1}(x) = \$3,500 \times 3x

b) Two customers per tour: R2(x)=$3,500×2xR_{2}(x) = \$3,500 \times 2x

Break-even volume:

a) in case the helicopter is filled to capacity:


C(x)=R1(x);$42,500+$6,500×x=$3500×3x;$4,000×x=$42,500;x=10.62511 tours\begin{array}{l} C(x) = R_{1}(x); \\ \$42,500 + \$6,500 \times x = \$3500 \times 3x; \\ \$4,000 \times x = \$42,500; \\ x = 10.625 \approx 11 \text{ tours} \end{array}


b) in case the helicopter carries two customers:


C(x)=R2(x);$42,500+$6,500×x=$3500×2x;$500×x=$42,500;x=85 tours\begin{array}{l} C(x) = R_{2}(x); \\ \$42,500 + \$6,500 \times x = \$3500 \times 2x; \\ \$500 \times x = \$42,500; \\ x = 85 \text{ tours} \end{array}


Answer: 11 tours for the helicopter filled to capacity; 85 tours for the helicopter carrying two customers.

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