Question #44261

Consider the following short-run production function (where L = variable input, Q = output):
Q = 6L3 – 0.4L3

a. Determine the marginal product function (MPL).
b. Determine the average product function (APL).
c. Find the value of L that maximises Q.
d. Find the value of L at which the marginal product function takes on its maximum value.
e. Find the value of L at which the average product function takes on its maximum value.
1

Expert's answer

2014-07-18T10:29:56-0400

Answer on Question #44261 – Economics – Microeconomics

Consider the following short-run production function (where L=L = variable input, Q=Q = output):


Q=6L30.4L2Q = 6L^3 - 0.4L^2


a. Determine the marginal product function (MPL).

MPL is the derivative of production function, so MPL = Q=18L20.8LQ' = 18L^2 - 0.8L

b. Determine the average product function (APL).


APL=Q/L=6L20.4LAPL = Q/L = 6L^2 - 0.4L


c. Find the value of L that maximizes Q.

Q is maximized, when Q=MPL=0Q' = MPL = 0, so:


18L20.8L=0L(18L0.8)=0L=0 or L=0.8/18=0.044\begin{array}{l} 18L^2 - 0.8L = 0 \\ L^*(18L - 0.8) = 0 \\ L = 0 \text{ or } L = 0.8/18 = 0.044 \\ \end{array}


d. Find the value of L at which the marginal product function takes on its maximum value.

In our case MPL has no maximal points, so there is no maximal value.

e. Find the value of L at which the average product function takes on its maximum value.

In our case APL has no maximal points, so there is no maximal value.

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