A)
x=0.5l21k21
Given that Pl=$5 and Pk=$10 and C=$600
X=0.5l21k21+λ(60−5l−10k)
Xl=0.25l−21k21−5λ=0 .......1)
Xk=0.25l21k−21−10λ=0 .....2)
Xλ=60−5l−10k=0 .......3)
0.25l21k−210.25l−21k21=105
lk=105
l=2k
Substituting l in (3)
600−5(2k)−10k=0
600−20k=0
kˉ=30
lˉ=2(30)=60
B)MRTSlk=l−k
At the optimum,
MRTSlk=60−30=2−1
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