Question #30116

4. Given the following production and cost function
Given by Y=15L0.4 K0.5 (Production function)
C=W1L+W2K+100 (Cost Function)
Where L= labor, K= capital,
A) Compute the following
i. APPL (2 points)
ii. APPK (2 points)
iii. MPPL (2 points)
iv. MPPK (2 points)
v. Marginal rate of technical substitution of labour for capital /MRTSLK(2 points)
vi. Expansion path (2 points)
vii. Elasticity of substitution (2 points)
viii. Return to scale (2 points)
ix. Indicate the relationship between elasticity of substitution and scale. (2 points)

Expert's answer

Task: 4. Given the following production and cost function

Given by Y=15L0.4Y = 15L0.4 K0.5 (Production function)

C=W1L+W2K+100C = W1L + W2K + 100 (Cost Function)

Where L=L = labor, K=K = capital,

A) Compute the following

i. APPL (2 points)

ii. APPK (2 points)

iii. MPPL (2 points)

iv. MPPK (2 points)

v. Marginal rate of technical substitution of labour for capital /MRTSLK(2 points)

vi. Expansion path (2 points)

vii. Elasticity of substitution (2 points)

viii. Return to scale (2 points)

ix. Indicate the relationship between elasticity of substitution and scale. (2 points)

Solution:

i. Average product (AP) is the total product divided by the number of units of variable factor used to produce it.


APPL=YLAPPL = \frac{Y}{L}APPL=15L0.4K0.5L=15L0.6K0.5=15K0.5L0.6APPL = \frac{15L^{0.4}K^{0.5}}{L} = 15L^{-0.6}K^{0.5} = \frac{15K^{0.5}}{L^{0.6}}


ii. We can find APPK is the same way:


APPK=YKAPPK = \frac{Y}{K}APPK=15L0.4K0.5K=15L0.4K0.5APPK = \frac{15L^{0.4}K^{0.5}}{K} = \frac{15L^{0.4}}{K^{0.5}}


iii. Marginal product (MP) is the change in total product resulting from the use of one additional unit of the variable factor.


MPPL=YL=6K0.5L0.6MPPL = \frac{\partial Y}{\partial L} = 6\frac{K^{0.5}}{L^{0.6}}


iv. We can find MPPK in the same way as MPPL:


MPPK=YK=7.5L0.4K0.5MPPK = \frac{\partial Y}{\partial K} = 7.5\frac{L^{0.4}}{K^{0.5}}


v. The Marginal Rate of Technical Substitution (MRTS) is the amount by which the quantity of one input has to be reduced (ΔK)(-\Delta K) when one extra unit of another input is used (ΔL=1)(\Delta L = 1), so that output remains constant (Y=const).


MRTSLK=MPPLMPPKMRTSLK=6K0.5L0.6;7.5L0.4K0.5=0.8KL\begin{array}{l} MRTS_{LK} = \frac{MPPL}{MPPK} \\ MRTS_{LK} = \frac{6K^{0.5}}{L^{0.6}}; \frac{7.5L^{0.4}}{K^{0.5}} = 0.8 \frac{K}{L} \end{array}


vi. As we have Cost Function given, we can find the expansion path. But first of all we should find prices for the resources. W1W_1 is the price for the labor, W2W_2 is the reward for the capital. Expansion path is the next:


MPPLMPPK=W1W20.8KL=W1W2K=LW10.8W2\begin{array}{l} \frac{MPPL}{MPPK} = \frac{W_1}{W_2} \\ \frac{0.8K}{L} = \frac{W_1}{W_2} \\ K = L \frac{W_1}{0.8W_2} \end{array}


vii. The elasticity of substitution is:


E=ln(LK)ln((MRTSLK))E = \frac{\partial \ln \left(\frac{L}{K}\right)}{\partial \ln \left(\left(M R T S_{LK}\right)\right)}

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