W = 80 − 3 Q W=80-3Q W = 80 − 3 Q
W = 30 + 2 Q W=30+2Q W = 30 + 2 Q
At equilibrium, demand=supply;
so, 80 − 3 Q = 30 + 2 Q 80-3Q=30+2Q 80 − 3 Q = 30 + 2 Q
like terms, 5Q=50;
5 Q 5 = 50 5 \frac{\cancel5Q}{\cancel5}=\frac{50}{5} 5 5 Q = 5 50
Q = 50 5 = 10 Q=\frac{50}{5}=10 Q = 5 50 = 10
We can find W by substituting Q with 10 in one of the equations.
W = 80 − ( 3 × 10 ) = 50 W=80-(3\times10)=50 W = 80 − ( 3 × 10 ) = 50
So, equilibrium point is at 50 for W and 10 for Q.
Elasticity:
C h a n g e i n W = 50 − 0 = 50 Change in W=50-0=50 C han g e inW = 50 − 0 = 50
A v e r a g e o f W = 50 + 0 2 = 25 Average of W=\frac{50+0}{2}=25 A v er a g eo f W = 2 50 + 0 = 25
P e r c e n t a g e c h a n g e = 50 25 × 100 = 200. Percentage change=\frac{50}{25}\times100=200. P erce n t a g ec han g e = 25 50 × 100 = 200.
Change in QC h a n g e i n Q = 10 − 0 = 10 Change in Q=10-0=10 C han g e in Q = 10 − 0 = 10
A v e r a g e o f Q = 10 + 0 2 = 5 Average of Q=\frac{10+0}{2}=5 A v er a g eo f Q = 2 10 + 0 = 5
P e r c e n t a g e c h a n g e = 10 5 × 100 = 200. Percentage change=\frac{10}{5}\times100=200. P erce n t a g ec han g e = 5 10 × 100 = 200.
E l a s t i c i t y = p e r c e n t a g e c h a n g e i n W p e r c e n t a g e c h a n g e i n Q = 200 200 = 1 Elasticity=\frac{percentage change in W}{percentage change in Q}=\frac{200}{200}=1 El a s t i c i t y = p erce n t a g ec han g e in Q p erce n t a g ec han g e inW = 200 200 = 1
Elasticity is 1.
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