U(10X21Y41)
Px=4
Py=2
Income= 100
a)
MuyMux=PyPx
Mux=5x2−1Y41
Muy=2.5x21Y4−3
2.5x21Y4−35x2−1Y41=PxPy
2.5X5Y=PyPx
Y=5Py2.5XPx
=Py0.5XPx ...........(i)
X=2.5Px5PyY
X=Px2Py .........(i
100=Px(Px2PyY)+PyY
100=2PyY+PyY
100=PyY(2+1)
PyY=3100
Y∗=3Py100......DemandfunctionforY
100=PxX+Py(Py0.5PxX)
PxX=1.5100
X∗=1.5Px100.......Demand function of X
b) Maximizing Levels of X and Y
2.5x21Y4−35x2−1Y41=24
2.5X5Y=24
Y=X
Px×X=Py×Y=m
4Y+2Y=100
Y=6100=350
X= 350
c) Maximum Utility= 350+350=3100=33.33
d) Marginal rate of substitution of the X and Y
MRSxy=(δxδy)δU
MRSxy=5×2.50.125 =0.01
MRSyx=2.5×50.125 =0.01
There is no difference in the MRS
Comments