Consider the following hypothesis test:
H 0 : μ ≥ 21
H a : μ < 21
A sample of 50 provided a sample mean of 20.4. The population standard deviation is 2.
a) Compute the value of the test statistic.
b) What is the p-value?
c) Using α = 0.05, what is your conclusion?
d) Write the rejection rule using the critical value. What is your conclusion?
"H_0: \\mu \u2265 21 \\\\\n\nH_1: \\mu < 21 \\\\\n\nn = 50 \\\\\n\n\\bar{x} = 20.4 \\\\\n\n\\sigma = 2"
a) Test-statistic
"Z = \\frac{\\bar{x} - \\mu}{\\sigma \/ \\sqrt{n}} \\\\\n\nZ = \\frac{20.4 -21}{2 \/ \\sqrt{50}} = -2.121"
b) P-value = P(Z< -2.121)
= 0.0169
c) α=0.05
Since p-value is less than α, we reject the null hypothesis and conclude that "\\mu < 21"
d) Left-tailed test
Critical value of Z = -1.645
Since "Z < Z_{critical}" we reject the null hypothesis and conclude that "\\mu < 21"
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