Question

Find the derivatives of the following functions.

• y=(4x+3)/ln[2x^2+3x-5]

Answer 1

$y=\frac{4x+3}{\ln(2x^2+3x-5)},$

$y'=\frac{4\ln(2x^2+3x-5)-\frac{(4x+3)^2}{2x^2+3x-5}}{\ln^2(2x^2+3x-5)}.$