Question #262617

Qx=200-px+2py+.03y where px=10 py=15 y=1000.

Find the PED.


1
Expert's answer
2021-11-09T10:47:59-0500

PED=δQ/δPP/QPED=\delta Q/\delta P*P/Q

PED=1P/QPED=-1*P/Q

Q=20010+2(15)+0.03(1000)Q=200-10+2(15)+0.03(1000)

Q=20010+30+30Q=200-10+30+30

Q=250Q=250

PED=110/250PED=-1*10/250

PED=0.04PED=-0.04


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