Solution:
i.). The benefit of N10 between A and B is maximized where:"\\frac{MU_{A} }{P_{A}} = \\frac{MU_{B} }{P_{B}}"
= "\\frac{2z - 20 - 2x}{x} = \\frac{2z - 42 + y}{y}"
X = "\\frac{2y(z-10)}{2z - 42+y}"
10 = x + y
"10 = \\frac{2y(z-10)}{2z - 42+y} +y"
ii.). Marginal Naira will yield:
z = "\\frac{420-92y+3y^{2} }{4(y-5)}"
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