Solution:
i.). The benefit of N10 between A and B is maximized where:MUAPA=MUBPB\frac{MU_{A} }{P_{A}} = \frac{MU_{B} }{P_{B}}PAMUA=PBMUB
= 2z−20−2xx=2z−42+yy\frac{2z - 20 - 2x}{x} = \frac{2z - 42 + y}{y}x2z−20−2x=y2z−42+y
X = 2y(z−10)2z−42+y\frac{2y(z-10)}{2z - 42+y}2z−42+y2y(z−10)
10 = x + y
10=2y(z−10)2z−42+y+y10 = \frac{2y(z-10)}{2z - 42+y} +y10=2z−42+y2y(z−10)+y
ii.). Marginal Naira will yield:
z = 420−92y+3y24(y−5)\frac{420-92y+3y^{2} }{4(y-5)}4(y−5)420−92y+3y2
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments