a)
n=1.5xn−100xn,n=\frac{1.5x_n-100}{x_n},n=xn1.5xn−100,
b)
R2=limn→∞p(n)=limn→∞1.5xn−100xn=1.5,R_2=\underset{ n \to \infin}{\lim}p(n)=\underset{ n \to \infin}{\lim}\frac{1.5x_n-100}{x_n}=1.5,R2=n→∞limp(n)=n→∞limxn1.5xn−100=1.5,
c)
Q=4400−1200⋅1.5100=26.Q=\frac{4400-1200\cdot 1.5}{100}=26.Q=1004400−1200⋅1.5=26.
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