"Q=6L^2-0.4L^3"
Differentiating Q w.r.t. L:
"\\frac{\\delta Q}{\\delta L}=12L-1.2L^2"
Equate "\\frac{\\delta Q}{\\delta L}=0"
"12L-1.2L^2=0"
Solving the equation quadratically, we get:
"L=\\frac{-12}{-2.4}"
"L=5."
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