You are the manager of a firm that produces furniture. All your clients are in Kumasi (K) and Accra (A). Suppose the monthly inverse demand function for your furniture in in Accra and Kumasi combined is π = 1200 β 4π. Because of prohibitive cost of transporting furniture between Accra and Kumasi, you set up two plants, one in each town. The cost of producing furniture at each facility is given by πΆA (πA ) = 8000 + 6πA2 and πΆK(πK) = 8000 + 6πK2 where π = πA + πK and πA and πK are the quantity of furniture produced at Accra and Kumasi respectively. Determine the profit-maximizing amounts of electricity to produce in the two facilities, the optimal price and the profit.
Solution:
Profit maximizing level of output: MR = MC
Derive MR:
TR = P x Q = (1,200 β 4Q) Q = 1,200Q β 4Q2
TR = 1,200Q β 4Q2
MR = "\\frac{\\partial TR} {\\partial Q}" = 1,200 β 8Q
MR = 1,200 β 8QA β 8QK
Β
MR = MC1 and MR = MC2
TC1 (QA) = 8000 + 6QA2
MC1 (QA) = "\\frac{\\partial TC_{1} } {\\partial Q_{A} }" = 12QA
TC2 (QK) = 8000 + 6QK2
MC2 (QK) "\\frac{\\partial TC_{2} } {\\partial Q_{K} }" = 12QK
Q = QA + QK
Set the two equations:
MC1 (QA) = MR
MC2 (QK) = MR
Β
1). 1,200 β 8QA β 8QK = 12QA
1200 β 8QK = 12QA + 8QA
1200 β 8QK = 20QA
Divide all sides by 20:
60 β 0.4QK = QA
QA = 60 β 0.4QK
Substitute for QK in the second function:
2.). 1200 β 8QA β 8QK = 12QK
1200 β 8(60 β 0.4QK) β 8QK = 12QK
1200 β 480 + 3.2QK β 8QK = 12QK
720 = 12QK + 8QK β 3.2QK
720 = 16.8QK
QK = 43
QA = 60 β 0.4QK = 60 β 0.4(43) = 60 β 17 = 43
QA = 43
Q = 43 + 43 = 86
The profit-maximizing amounts of electricity to produce in the two facilities = 86 Units
The optimal price:
P = 1200 β 4Q = 1200 β 4(86) = 1200 β 344 = 856
The optimal price = 856
Β
Profit = TR β TC
TR = P "\\times" Q = 856 "\\times" 86 = 73,616
TC = TC1 + TC2
TC1 = 8000 + 6πA2Β = 8000 + 6(432) = 8000 + 11094 = 19,094
TC2 = = 8000 + 6πK2Β = 8000 + 6(432) = 8000 + 11094 = 19,094
TC = 19,094 + 19,094 = 38,188
Profit = 73,616 β 38,188 = 35,428
Profit = 35,428
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