Question

40LK-10L²-5K²

Answer 1

$40LK-10L^2-5K^2$

Assuming $K=1$,

We get:

$40L-10L^2-5$

$10L^2-40L+5=0$

Solving the above equation quadratically,

$L=\frac {40+(1400)^\frac{1}{2}}{20}$

$L=4$