Solution:
To maximize revenue, first derive the revenue function from the demand function:
Demand function: 10P + 3Q = 60
"P = 6 - \\frac{3}{10}Q"
Revenue function = P "\\times" Q
Revenue function = "(6 - \\frac{3}{10}Q) \\times Q = 6Q - \\frac{3}{10}Q^{2}"
To derive the maximizing revenue quantity, find the first derivative and set it to zero:
First derivative:
"\\frac{\\partial R} {\\partial Q} = 6 - \\frac{6}{10}Q"
"6 - \\frac{6}{10}Q = 0"
"6 =\\frac{6}{10}Q"
Q = 10
Revenue maximizing quantity = 10
Substitute in the price function to determine maximizing price:
"P = 6 - \\frac{3}{10}Q"
"P = 6 - \\frac{3}{10}(10)"
P = 6 – 3 = 3
P = 3
Revenue maximizing price = 3
Maximizing Revenue = P "\\times" Q = 3 x 10 = 30
Consumer surplus = (0.5) (10) (6-3)
Consumer surplus = 15
Consumer surplus will be much higher when the hostel operators decide to maximize sales revenue instead of profit
Calculating producer surplus at equilibrium:
At equilibrium: Qd = Qs
Qd: 10P + 3Q = 60
"Q = 20 - \\frac{10}{3}P"
Qs: P = Q – 0.5
Q = P + 0.5
Set Qd = Qs
"20 - \\frac{10}{3}P = P + 0.5"
Multiply both sides by 3:
60 – 10P = 3P + 1.5
60 – 1.5 = 3P + 10P
58.5 = 13P
P = 4.5
Equilibrium Price = 4.5
Substitute in either demand or supply equation to derive equilibrium quantity:
Demand function:
"Q = 20 - \\frac{10}{3}P"
"Q = 20 - \\frac{10}{3}(4.5)"
Q = 20 – 15
Q = 5
Supply function:
Q = P + 0.5
Q = 4.5 + 0.5
Q = 5
Equilibrium Quantity = 5
Producer surplus at equilibrium:
½ "\\times" (5) "\\times" (4.5 – 0.5)
½ "\\times"20 = 10
Producer surplus at equilibrium = 10
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