Suppose a consumer’s utility function is given a U = 100X0.25Y0.75.The prices of the two commodities X and Y are Birr 2 and Birr 5 per unit respectively. If the consumer’s income is Birr 280, how many units of each commodity should the consumer buy to maximize his/her utility?
U = 100X0.25Y0.75
Budget constraint is
"2x + 5y = 280"
Maximize utility function
subject to the budget constraint
Max U = 100X0.25Y0.75
"2x + 5y \u2264 280"
"x\u22650 ,\ny\u22650"
We introduce a lagrangian function to our function
"L =" 100X0.25Y0.75 + ƛ ("280- 2x - 5y" )
FIRST ORDER CONDITIONS
ɚL/ɚX = 25X-0.75Y0.75 - ƛ2 = 0 .......EQUATION 1
ɚL/ɚY=75X0.25Y-0.25- ƛ5 = 0 ......... EQUATION 2
ɚL/ɚ"\u019b =" ƛ = 280- 2x - 5y = 0 ..............EQUATION 3
WE COMBINE EQUATION 1 AND 2
ƛ=(25X-0.75Y0.75 ) ÷ 2 = (75X0.25Y-0.25 ) ÷ 5
SOLVING THIS WE GET;
5 ÷6 =X ÷ Y
Thus x= 0.833y
y= 1.2x
Using equation three we substitute one of the above rquations
280- 2x - 5y = 0
2x- 5y=280 but x= 0.833y
0.833y x 2 - 5y=280
Solving this we get
y= 168 units
From y= 1.2x we substitute y = 168 and solve to find x
168 = 1.2x
x = 140 units
Therefore the consumer maximizes utility at y= 168 units and x = 140 units
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