Question #222508
1. Maximize U(x,y)=xy subjected to Px=2, Py=8 and M=160
1
Expert's answer
2021-08-04T10:14:06-0400

MuxMuy=PxPyU(x,y)=x×y\frac{Mux}{Muy}=\frac{Px}{Py}\\U(x,y)=x\times y

Mux=dudx=yMuy=dudy=xMux=\frac{du}{dx}=y\\Muy=\frac{du}{dy}=x\\

now putting values

yx=282x=8yx=8yI=Px×X+Py×Y160=2×4y+8y160=8y+8y160=16yy=10\frac{y}{x}=\frac{2}{8}\\2x=8y\\x=8y\\I=Px\times X+Py\times Y\\160=2\times 4y+8y\\160=8y+8y\\160=16y\\y=10

now putting value of y in x

x=4×yx=4×10x=40x=4\times y\\x=4\times10\\x=40\\

utility is maximum when

x=40 and y=10

U(40,10)=40×10U=400U(40,10)=40\times 10\\U=400


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