Given the demand function, the inverse demand can be written as:
"Q(p)=50\u22125p"
"Y= 50-5p"
"5p=50-Y"
"P=10-\\frac{1}{5}Y"
The cost function is given as:
"c(Y) = 4Y"
Thus, given the demand and cost, the profit function can be written as:
Profit(π) = Total Revenue−Total Cost
"Profit [\u03c0]= (10\u2212\\frac{1}{5}Y)Y\u22124Y"
Differentiating the profit function to solve for profit-maximizing output:
"=> \\frac{\u2202\u03c0}{\u2202Y}=10\u2212\\frac{2}{5}Y\u22124=0"
"=>6\u2212\\frac{2}{5}Y\u22124=0"
"=>\\frac {2}{5}Y=6"
"Y=\\frac{6\u00d75}{2}=15"
Hence, the profit-maximizing output is 15 units.
Given the output, it can be substituted in the inverse demand function to find the price:
"p=10\u2212[\\frac{1}{5}\u00d715]"
"p =10\u22123"
"p=7"
The optimal price for the monopolist competitor to charge is 7.
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