Solution
U=X1aX2b
M=P1X1+P2X2
MUx1=DX1DU=aX1a-1X2b-1
maximizing utility
MUx2MUx1 =P2P1
solve for X2
bX1aX1−a+1aX2bX2−b+1 =P2P1
bX1aX2 =P2P1 X2= aP2bP1
M=P1X1+P2X2
substituting X2
M= P1X1+P2 aP2bP1 X1
M=aaP1X1 +abP1X1
M=a(a+b)P1 X1
X1= (a+b)P1aM
X2= aP2bP1 x (a+b)P1aM
X2=(a+b)P2bM
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