Q1=24−0.2P1
P1=0.224−Q1
Q2=10−0.05P2
P2=0.0510−Q2
Average cost; AC=40+Q35
Total Revenue; TR=P×Q
so,
TR1=P1×Q1
=0.224−Q1×Q1
=120Q1−5Q12
TR2=P2×Q2
=0.0510−Q2×Q2
=200Q2−20Q22
marginal revenue=First derivative of total revenue
MR1=dQ1dTR1
=120−10Q1
MR2=dQ2dTR2
=200−40Q2
Average cost; AC=(40−Q35)×Q
=40Q−35
Marginal cost = First derivative of total cost
MC=dQdTC
=40
Profit maximizing quantity of the firm will be when;
MR!=MR2=MC
when;
MR1=MC
120−10Q1=4010Q1=120−40Q1=8
then; P1=0.224−Q1
=0.224−8
=80
and when
MR2=MC200−40Q2=4040Q2=200−40Q2=40160Q2=4
then
P2=0.0510−Q1
=0.0510−4
=120
Therefore the prices firm will charge with discrimination are P1=80 and P2=120
Comments
Nice one