Question #199040

The following are two distinct demand functions: 𝑞1=24−0.2𝑃1 and 𝑞2=10−0.05𝑃2. The average cost AC=40+35/q. What price the firm will change with discrimination?


Expert's answer

Q1=24−0.2P1Q_1=24-0.2P_1

P1=24−Q10.2P_1=\frac{24-Q_1}{0.2}

Q2=10−0.05P2Q_2=10-0.05P_2

P2=10−Q20.05P_2=\frac{10-Q_2}{0.05}

Average cost; AC=40+35QAC=40+\frac{35}{Q}

Total Revenue; TR=P×QTR=P\times Q

so,

TR1=P1×Q1TR_1=P_1\times Q_1

=24−Q10.2×Q1=\frac{24-Q_1}{0.2}\times Q_1

=120Q1−5Q12=120Q_1-5Q_1^2

TR2=P2×Q2TR_2=P_2\times Q_2

=10−Q20.05×Q2=\frac{10-Q_2}{0.05}\times Q_2

=200Q2−20Q22=200Q_2-20Q_2^2

marginal revenue=First derivative of total revenue

MR1=dTR1dQ1MR_1=\frac{dTR_1}{dQ_1}

=120−10Q1=120-10Q_1


MR2=dTR2dQ2MR_2=\frac{dTR_2}{dQ_2}

=200−40Q2=200-40Q_2


Average cost; AC=(40−35Q)×QAC=(40-\frac{35}{Q})\times Q

=40Q−35=40Q-35

Marginal cost = First derivative of total cost


MC=dTCdQMC=\frac{dTC}{dQ}

=40=40


Profit maximizing quantity of the firm will be when;

MR!=MR2=MCMR_!=MR_2=MC

when;

MR1=MCMR_1=MC\\

120−10Q1=4010Q1=120−40Q1=8120-10Q_1=40\\10Q_1=120-40\\Q_1=8


then; P1=24−Q10.2P_1=\frac{24-Q_1}{0.2}


=24−80.2=\frac{24-8}{0.2}


=80=80


and when

MR2=MC200−40Q2=4040Q2=200−40Q2=16040Q2=4MR_2=MC\\200-40Q_2=40\\40Q_2=200-40\\Q_2=\frac{160}{40}\\Q_2=4

then

P2=10−Q10.05P_2=\frac{10-Q_1}{0.05}\\

=10−40.05=\frac{10-4}{0.05}


=120=120


Therefore the prices firm will charge with discrimination are P1=80 and P2=120P_1=80\space and\space P_2=120


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